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What is the magnitude of the net magnetic force that acts on the loop? A long, straight wire carries a 10.0-A current in the +y direction. Next to the wire is a square copper loop that carries a 2.00-A current (to the right). The length of each side of the square is 1.00 m. ... (Asked by kate)
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The forces acting on the 2 wires perpendicular to the long wire are equal and opposite and hence cancel. Now the force on the wire right beside the long wire is zero. Force on the last wire parellel to the long wire is F = BIL ie F=((10^-7)10/(2pi1.0)) 2 * 1.0 F = (10^-6)/pi Newton...(Answered by Karthik I)

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What is the magnitude of the magnetic force exerted on the particle? A particle with a mass of 6.64 × 10–27 kg and a charge of +3.20 × 10–19 C is accelerated from rest through a potential difference of 2.45 × 106 V. The particle then enters a uniform 1.60-T magnetic field. If the particle's velocity is perpendicular to the magnetic field at all times, what is the magnitude of the magnetic force exerted on the particle? ... (Asked by kate)
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Magnetic Force = qvB Now the particle is accelrated from rest and the electric potential energy gets converted to kinetic energy. ie KE = q * V = 6.64 * 10^-27 * 2.45 * 10^6 J But KE = 0.5 * m * v * v Hence find velocity v. Then subsitute in first equation to find the magnetic force....(Answered by Karthik I)

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What is the magnitude of the velocity of the protons? A proton source injects H(+) ions at low speed. A beam of protons (each having a rest mass 1.6710^-27 kg) is moving in a circle of radius 80.0 cm between 2 circular flat electromagnets. If these electromagnets supply a force of 8.0010^-13 N on each proton directed toward the center of revolution, what is the magnitude of the velocity of the protons? The proton motion is circular and the speeds involved are small compared with the velocity of light. Take the value of squareroot of 3.83 to be 1.96. ... (Asked by willydavidjr)
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Since the proton is moving in a circular pattern, the force given is the centripetal force. I know that it it worded weirdly, but I believe that is just to throw you off. The equation for the centripetal force due to circular motion is F = m * (v^2) / r where F is the force, m is the mass of the object, v is the velocity, and r is the radius of the circular path. So we set up the following: 8.00 * 10^-13 N = (1.67 * 10 ^-27 kg) * (v^2) / (0.8 m) I used ...(Answered by bdecker202)

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The coefficent of kinitic friction between the block & surface is .33. The magnitude of friction force is 77N. The coefficent of kinitic friction between the block & surface is .33. The magnitude of friction force is 77N. What is the weight of the block? Please show work if possible. Thanks. ... (Asked by lenoxdesignerjewelry)
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Fk = MFn 77 N = .33 Fn Fn = 233.3333 N Fn = mg = weight...(Answered by pdate07)

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The coefficent of kinitic friction between the block & surface is .33. The magnitude of friction force is 77N. The coefficent of kinitic friction between the block & surface is .33. The magnitude of friction force is 77N. What is the weight of the block? Please show work, if possible. Thanks. ... (Asked by poolking678)
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14.8 kg...(Answered by Just Try It)

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Magnitude of a vector? Ok. I would like to know the formula for the magnitude of a vector. 1. What is the magnitude of the vector(4,-2)? 2. If two lines are parallel, what is the product of their slopes? 3. What is the distance between M(-1,2,4) and N(-1,-1,8)? Im not asking so that i can just get the answers for my homework. I'm trying to check my answers/theories(lol). If you only want to give me the formula then I'd be happy with that. Thanks ... (Asked by peaceful_708)
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1) sqrt[ (4-0)^2 + (-2-0)^2] = sqrt(16+4) = sqrt(20) = 2sqrt(5) 2) I think you mean perpendicular. The product of two perpendicular lines is always -1. If two lines are parallel, then they have the same slope. So the product of two parallel lines is not always the same number. If the slope is 3, then the product is 33 = 9 If the slope is 5, then the product is 55 = 25 You could say that the product of two parallel lines is a perfect square. 3) Just use the normal distance formula (except now you have 3 coordinates). sqrt[(-1-(-1))^2 + (2-(-1))^2 + (4-8)^2] = sqrt(0^2 + 3^2 + (-4)^2) = sqrt(0+9+16) = ...(Answered by MsMath)

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magnitude? If the masss of a car is 900 kg and the acceleration is 0-60 mph (0-27 m/s) in 7.5 seconds, what is the magnitude of the average acceleration of the car? ... (Asked by lisataho)
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I don't know. seek the answer in the holy bible and pray for guidance in your physics class. Jesus and the Lord peform many miracles for those with faith i will pray for you. here is a prayer for you: "Dear god i suck at physics i am so stupid and lazy that i get people i don't even know to do my homework. in Jesus' name. amen" 'May the force be with you young padawan'...(Answered by CoolCrab)

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Calculate the magnitude of the resultant of a pair of 100-km/h velocity vector...? Calculate the magnitude of the resultant of a pair of 100-km/h velocity vectors that are at right angles to each other. ... (Asked by Melissa)
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200.000 millponds...(Answered by decaracas)

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What is the magnitude of normal force acting on 75kg child? What is the magnitude of normal force acting on 75kg child? Please show your work if possible. Thanks. ... (Asked by myfreecell)
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735 N...(Answered by buccinator)

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What is the magnitude of normal force acting on 75kg child? What is the magnitude of normal force acting on 75kg child? Please show work, if possible. Thanks. ... (Asked by khuram678)
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If the MASS of the child is 75kg and the child is on a horizontal surface, the normal force is 75*gN. If the WEIGHT of the child is 75kg, the normal force is 75N. If the weight is what is meant, the units given should have been kgwt. 1kgwt = 1N. This is confusing because we tend to use weight and mass as meaning the same thing. If we place an object on a scale, and the mass of the object is 1kg, the scale should read 1N, not 1kg; unfortunately the scales are ...(Answered by gp4rts)

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What is the magnitude of the net magnetic force that acts on the loop? A long, straight wire carries a 10.0-A current in the +y direction. Next to the wire is a square copper loop that carries a 2.00-A current (to the right). The length of each side of the square is 1.00 m. ... (Asked by kate)
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A.
The forces acting on the 2 wires perpendicular to the long wire are equal and opposite and hence cancel. Now the force on the wire right beside the long wire is zero. Force on the last wire parellel to the long wire is F = BIL ie F=((10^-7)10/(2pi1.0)) 2 * 1.0 F = (10^-6)/pi Newton...(Answered by Karthik I)

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What is the magnitude of the velocity of the protons? A proton source injects H(+) ions at low speed. A beam of protons (each having a rest mass 1.6710^-27 kg) is moving in a circle of radius 80.0 cm between 2 circular flat electromagnets. If these electromagnets supply a force of 8.0010^-13 N on each proton directed toward the center of revolution, what is the magnitude of the velocity of the protons? The proton motion is circular and the speeds involved are small compared with the velocity of light. Take the value of squareroot of 3.83 to be 1.96. ... (Asked by willydavidjr)
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A.
Since the proton is moving in a circular pattern, the force given is the centripetal force. I know that it it worded weirdly, but I believe that is just to throw you off. The equation for the centripetal force due to circular motion is F = m * (v^2) / r where F is the force, m is the mass of the object, v is the velocity, and r is the radius of the circular path. So we set up the following: 8.00 * 10^-13 N = (1.67 * 10 ^-27 kg) * (v^2) / (0.8 m) I used ...(Answered by bdecker202)

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The coefficent of kinitic friction between the block & surface is .33. The magnitude of friction force is 77N. The coefficent of kinitic friction between the block & surface is .33. The magnitude of friction force is 77N. What is the weight of the block? Please show work if possible. Thanks. ... (Asked by lenoxdesignerjewelry)
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A.
Fk = MFn 77 N = .33 Fn Fn = 233.3333 N Fn = mg = weight...(Answered by pdate07)

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Magnitude of a vector? Ok. I would like to know the formula for the magnitude of a vector. 1. What is the magnitude of the vector(4,-2)? 2. If two lines are parallel, what is the product of their slopes? 3. What is the distance between M(-1,2,4) and N(-1,-1,8)? Im not asking so that i can just get the answers for my homework. I'm trying to check my answers/theories(lol). If you only want to give me the formula then I'd be happy with that. Thanks ... (Asked by peaceful_708)
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A.
1) sqrt[ (4-0)^2 + (-2-0)^2] = sqrt(16+4) = sqrt(20) = 2sqrt(5) 2) I think you mean perpendicular. The product of two perpendicular lines is always -1. If two lines are parallel, then they have the same slope. So the product of two parallel lines is not always the same number. If the slope is 3, then the product is 33 = 9 If the slope is 5, then the product is 55 = 25 You could say that the product of two parallel lines is a perfect square. 3) Just use the normal distance formula (except now you have 3 coordinates). sqrt[(-1-(-1))^2 + (2-(-1))^2 + (4-8)^2] = sqrt(0^2 + 3^2 + (-4)^2) = sqrt(0+9+16) = ...(Answered by MsMath)

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